(2√3√5)/(2√23√3) Rationalise the DenominatorSimplify 2√3√5 _____ 2√23√3 Ask questions, doubts, problems and we will help youJika x = (√2 √3 √5) dan y = (√2 √3 √5), maka tentukan nilai dari xy
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2^3/5*7^2/3
2^3/5*7^2/3-Rationalize the denominator 2√3√5 / 2√23√3 Share with your friends Share 0Rationalize the denominator #(2sqrt3sqrt5)/(2sqrt23sqrt3)# multiply by the conjugate #(2sqrt3sqrt5)/(2sqrt23sqrt3)*(2sqrt23sqrt3)/(2sqrt23sqrt3)#
1 Sqrt 2 Sqrt 3 Sqrt 5 1 Sqrt 2 Sqrt 3 Sqrt 5 In
23/7/21 (2根号3根号5)(2根号3 根号5) 怎么做—— 利用平方差公式(ab)(ab)=a^2b^2 (2根号3根号5)(2根号3根号5) =(2√3)^2(√5)^2 =125 =7 2(根号3根号2)(根号3 根号2)—— =2(根号3的平方—根号2的平方) =2(32) =2X1 =24/8/18 Rationalies the denominator and simplify (i) √3 √2/√3 √2 (ii) 5 2√3/7 4√3 (iii) 1 √2/3 2√26 Add 2√2 5√3 and √2 – 3√3 Solution (2√2 5√3) (√2 – 3√3) (21)√2(53)√3 3√22√3 7 Multiply 6√2 by 2√2 Solution 6√2 x 2√2 6 x 2 x √2 x √2 = 12 x 2 = 24 8 Rationalise the denominator of 1/√3 Solution To rationalise the denominator of 1/√3, we need to multiply numerator and denominator by √3
Click here👆to get an answer to your question ️ Rationales the denominator and simplify 2√(3)√(5)/2√(2) 3√(3)28/4/21 5(2√2√3√5)/{(2√2)^2(√3√5)^2} = 5(2√2√3√5)/(2√15) =(10√3015√525√3)/30 =(5√33√52√30)/6。6循環小数0324を,分数で表しなさい。 表現処理(3点) 6次の問に答えなさい。 数学的な考え方
An bilangan 2/ √2 √3 √5 =2/ √2 √3 √5 x √2 √3 √5/ √2 √3 √5 = 2(√2 √3 √5) / 2 2√6 3 5 = 2 (√2 √3 √5) / 2√6 = √2 √3 √5 / √6Answer√90Stepbystep explanation2√3√5√23√3=2√15*√6√3=2(√15*(18))2(√180)2(√2*√2*√3*√3*√5)so 2 and √2 gets cancelled √2*√3*√3*√5=√90please rate,
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您好: (√2 √3√5)²(√2√3√5)² =(√2√3√5√2√3√5)(√2√3√5√2√3√5) =2√2*(2√32√5) =4√64√10 a²3ab
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Incoming Term: 3 2/5 - 2 2/3, 3 2/5 x 2 2/3, 3 2/5 times 2 2/3, 2 3 5 2 3 6, 2^3/5*7^2/3, 2^x+3-5*2^x=3*2^-1, 2-3(1-2 x)=5-2(2x+3),
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